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Exercise 2183Calculus › Multivariable calculus › Multiple integralsM1Added 3 Nov 2026

Gaussian integral over $\mathbb{R}^2$

#Gaussian#polar#improper integral

Statement

Show that ∬R2e−(x2+y2) dx dy=π\displaystyle\iint_{\mathbb{R}^2}e^{-(x^2+y^2)}\,dx\,dy=\pi.

Hint

Polar coordinates: r2=x2+y2r^2=x^2+y^2, Jacobian rr.

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Solution

Polar. ∫02π∫0+∞e−r2r dr dθ=2π⋅12=π\int_0^{2\pi}\int_0^{+\infty}e^{-r^2}r\,dr\,d\theta=2\pi\cdot\frac12=\pi.

Conclusion. ∬R2e−(x2+y2) dx dy=π\iint_{\mathbb{R}^2}e^{-(x^2+y^2)}\,dx\,dy=\pi.

Corollary. ∫−∞+∞e−x2 dx=π\int_{-\infty}^{+\infty}e^{-x^2}\,dx=\sqrt\pi (Fubini argument).