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Exercise 256Calculus › Multivariable calculus › Multiple integralsHigh schoolAdded 3 Nov 2026

Double integral over a rectangle

#double integral#rectangle#iterated

Statement

Compute I=∬D2ysin⁡x dx dy\displaystyle I=\iint_D 2y\sin x\,dx\,dy where D=[0,π]×[0,1]D=[0,\pi]\times[0,1].

Hint

The bounds are independent: integrate one variable at a time.

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Solution

Iterated integral.
I=∫0π∫012ysin⁡x dy dx.I=\int_0^{\pi}\int_0^1 2y\sin x\,dy\,dx.

Inner. ∫012ysin⁡x dy=sin⁡x\int_0^1 2y\sin x\,dy=\sin x.

Outer. I=∫0πsin⁡x dx=[−cos⁡x]0π=2I=\int_0^{\pi}\sin x\,dx=[-\cos x]_0^{\pi}=2.

Conclusion. I=2I=2.