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Exercise 519Calculus › Multivariable calculus › Multiple integralsHigh schoolAdded 3 Nov 2026

Double integral over a triangular domain

#triangle#double integral#bounds

Statement

Compute I=∬Dsin⁡(x+y) dx dy\displaystyle I=\iint_D \sin(x+y)\,dx\,dy where D={x≥0, y≥0, x+y≤π}D=\{x\ge0,\ y\ge0,\ x+y\le\pi\}.

Hint

For x∈[0,π]x\in[0,\pi], yy ranges from 00 to π−x\pi-x.

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Solution

Iterated. I=∫0π∫0π−xsin⁡(x+y) dy dxI=\int_0^{\pi}\int_0^{\pi-x}\sin(x+y)\,dy\,dx.

Inner. [−cos⁡(x+y)]y=0y=π−x=1+cos⁡x[-\cos(x+y)]_{y=0}^{y=\pi-x}=1+\cos x.

Outer. I=∫0π(1+cos⁡x) dx=[x+sin⁡x]0π=πI=\int_0^{\pi}(1+\cos x)\,dx=[x+\sin x]_0^{\pi}=\pi.

Conclusion. I=πI=\pi.