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Exercise 1787Calculus › Multivariable calculus › Multiple integralsL1Added 3 Nov 2026

Volume using cylindrical coordinates

#cylindrical coordinates#volume#cone

Statement

Compute the volume of the solid bounded by z=0z=0, z=hz=h and x2+y2≤R2x^2+y^2\le R^2.

Hint

Cylindrical: x=rcos⁡θx=r\cos\theta, y=rsin⁡θy=r\sin\theta, z=zz=z; Jacobian rr.

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Solution

Cylindrical. 0≤r≤R0\le r\le R, 0≤θ≤2π0\le\theta\le2\pi, 0≤z≤h0\le z\le h.

Volume. V=∫02π∫0R∫0hr dz dr dθ=2π⋅R22⋅h=πR2hV=\int_0^{2\pi}\int_0^R\int_0^h r\,dz\,dr\,d\theta=2\pi\cdot\frac{R^2}{2}\cdot h=\pi R^2h.

Conclusion. V=πR2hV=\pi R^2h.