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Exercise 235Algebra › Equations and radicalsHigh schoolAdded 3 Nov 2026

A linear equation

#linear equation#solving#basic

Statement

Solve in R\mathbb{R} the equation
3(2x−1)−2(x+4)=5x−7.3(2x-1)-2(x+4)=5x-7.

Hint

Expand both sides, gather xx terms, and isolate xx.

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Solution

Expansion.
3(2x−1)−2(x+4)=6x−3−2x−8=4x−11.3(2x-1)-2(x+4)=6x-3-2x-8=4x-11.

Equation. 4x−11=5x−74x-11=5x-7.

Solving. 4x−5x=−7+114x-5x=-7+11, i.e. −x=4-x=4, so x=−4x=-4.

Verification. LHS: 3(−9)−2(0)=−273(-9)-2(0)=-27; RHS: −27-27. Correct.

Conclusion. x=−4x=-4.