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Exercise 462Algebra › Equations and radicalsHigh schoolAdded 3 Nov 2026

An exponential equation

#exponential equation#substitution#quadratic

Statement

Solve in R\mathbb{R} the equation
4x−5⋅2x+4=0.4^x-5\cdot2^x+4=0.

Hint

Set t=2x>0t=2^x>0.

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Solution

Substitution. t=2x>0t=2^x>0, so 4x=t24^x=t^2. The equation becomes
t2−5t+4=0,t^2-5t+4=0,
i.e. (t−1)(t−4)=0(t-1)(t-4)=0, so t=1t=1 or t=4t=4.

Back. 2x=1⇒x=02^x=1\Rightarrow x=0; 2x=4⇒x=22^x=4\Rightarrow x=2.

Conclusion. x∈{0,2}x\in\{0,2\}.