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Exercise 1802Calculus › Multivariable calculus › Partial derivativesL1Added 3 Nov 2026

Taylor expansion of order 2

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Statement

Give the Taylor expansion of f(x,y)=ex+yf(x,y)=e^{x+y} at (0,0)(0,0) up to order 22.

Hint

f(0)=1f(0)=1, ∇f(0,0)=(1,1)\nabla f (0,0)=(1,1), H(0,0)=(1111)H(0,0)=\begin{pmatrix}1&1\\1&1\end{pmatrix}.

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Solution

Expression.
f(h,k)=f(0,0)+∇f(0,0)⋅(h,k)+12(h,k)⋅H(0,0)⋅(h,k)+o((h2+k2)).f(h,k)=f(0,0)+ \nabla f(0,0) \cdot (h,k)+\frac{1}{2}(h,k) \cdot H(0,0) \cdot (h,k) +o((h^2+k^2)).

Simplified. f(h,k)=1+h+k+h22+hk+k22+o(h2+k2)f(h,k)=1+h+k+\frac{h^2}{2}+hk+\frac{k^2}{2}+o(h^2+k^2).

Conclusion. The expansion matches eh⋅ek=(1+h+h2/2+⋯ )(1+k+k2/2+⋯ )e^h\cdot e^k=(1+h+h^2/2+\cdots)(1+k+k^2/2+\cdots) to order 22.