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Exercise 258Calculus › Multivariable calculus › Partial derivativesHigh schoolAdded 3 Nov 2026

First partial derivatives

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Statement

Let f(x,y)=x2y+3xy2−2x+5f(x,y)=x^2y+3xy^2-2x+5. Compute ∂f∂x\frac{\partial f}{\partial x} and ∂f∂y\frac{\partial f}{\partial y}.

Hint

Differentiate with respect to one variable, treating the other as a constant.

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Solution

With respect to xx.
∂f∂x=2xy+3y2−2.\frac{\partial f}{\partial x}=2xy+3y^2-2.

With respect to yy.
∂f∂y=x2+6xy.\frac{\partial f}{\partial y}=x^2+6xy.

Conclusion. The two partial derivatives are as above.