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Exercise 523Calculus › Multivariable calculus › Partial derivativesL1Added 3 Nov 2026

Euler's theorem for homogeneous functions

#homogeneous functions#Euler#partial derivatives

Statement

Show that if ff is homogeneous of degree kk (i.e. f(tx,ty)=tkf(x,y)f(tx,ty)=t^kf(x,y)), then
xfx+yfy=kf.x f_x+y f_y=k f.

Hint

Differentiate the homogeneity identity with respect to tt and evaluate at t=1t=1.

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Solution

Identity. f(tx,ty)=tkf(x,y)f(tx,ty)=t^kf(x,y).

Differentiate. ddt\frac{d}{dt}: xfx(tx,ty)+yfy(tx,ty)=ktk−1f(x,y)x f_x(tx,ty)+y f_y(tx,ty)=k t^{k-1}f(x,y).

At t=1t=1. xfx(x,y)+yfy(x,y)=kf(x,y)xf_x(x,y)+yf_y(x,y)=kf(x,y).