Exercise 99Number theory › IrrationalityL1Added 3 Nov 2026
A general irrationality criterion
#criterion#irrationality#polynomial
Statement
Let be monic (i.e. ). Show that any real root of is irrational or an integer.
Hint
Rational root theorem: rational roots are integers dividing .
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Solution
Rational root theorem. Any rational root is of the form with , . Since , , so the root is an integer.
Conclusion. Any non-integer real root of is irrational.
Application. is monic, so is irrational; is monic, so is irrational.