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Exercise 1925Calculus › Multivariable calculus › Vector calculusL1Added 3 Nov 2026

Stokes with a hemisphere

#Stokes#hemisphere#closed curve

Statement

Compute ∮CF⃗⋅dr⃗\oint_C\vec F\cdot d\vec r for F⃗=(z,0,0)\vec F=(z,0,0) where CC is the boundary of the hemisphere x2+y2+z2=1x^2+y^2+z^2=1, z≥0z\ge0.

Hint

∇×F⃗=(0,0,−1)\nabla\times\vec F=(0,0,-1) if P=zP=z, Q=0Q=0, R=0R=0: ∇×F⃗=(0,−Pz,Qx)=(0,−1,0)\nabla\times\vec F=(0,-P_z,Q_x)=(0,-1,0) — recompute. ∇×(P,Q,R)=(Ry−Qz, Pz−Rx, Qx−Py)\nabla\times(P,Q,R)=(R_y-Q_z,\,P_z-R_x,\,Q_x-P_y); here P=z,Q=0,R=0P=z,Q=0,R=0 so curl =(0,1,0)=(0,1,0).

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Solution

Curl. ∇×F⃗=(0,1,0)\nabla\times\vec F=(0,1,0).

Use Stokes on flat disk at z=0z=0 with n⃗=(0,0,1)\vec n=(0,0,1): curl·n⃗=0\vec n=0.

Conclusion. ∮CF⃗⋅dr⃗=0\oint_C\vec F\cdot d\vec r=0.