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Exercise 1519Calculus › Multivariable calculus › Vector calculusL3Added 2 Nov 2026

Green-Riemann formula

#Green-Riemann#line integral#double integral

Statement

Let CC be the unit circle oriented counterclockwise. Compute
∫C(x2−y)dx+(y2+x)dy\int_C (x^2 - y)dx + (y^2 + x)dy
using the Green-Riemann formula.

Hint

Apply Green-Riemann: ∫CPdx+Qdy=∬D(∂Q∂x−∂P∂y)dx dy\int_C Pdx + Qdy = \iint_D \left( \frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} \right) dx\,dy.

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Solution

Identification. P(x,y)=x2−yP(x,y) = x^2 - y, Q(x,y)=y2+xQ(x,y) = y^2 + x.

Partial derivatives.
∂Q∂x=1,∂P∂y=−1.\frac{\partial Q}{\partial x} = 1, \qquad \frac{\partial P}{\partial y} = -1.
Hence
∂Q∂x−∂P∂y=1−(−1)=2.\frac{\partial Q}{\partial x} - \frac{\partial P}{\partial y} = 1 - (-1) = 2.

Green-Riemann.
∫CPdx+Qdy=∬D2 dx dy=2⋅Area(D)=2π.\int_C Pdx + Qdy = \iint_D 2 \, dx\,dy = 2 \cdot \text{Area}(D) = 2\pi.

Remark. One can also compute directly by parametrizing the circle, but Green-Riemann avoids trigonometric computation.