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Exercise 629Topology › Topology of Mn(ℝ)L1Added 4 Nov 2026

Continuity of the determinant

#determinant#continuity#polynomial

Statement

Show that det⁡:Mn(R)→R\det:M_n(\mathbb{R})\to\mathbb{R} is continuous.

Hint

The determinant is a polynomial in the entries.

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Solution

Polynomial in entries. By the Leibniz formula,
det⁡(A)=∑σ∈Snε(σ)∏i=1nai,σ(i).\det(A)=\sum_{\sigma\in S_n}\varepsilon(\sigma)\prod_{i=1}^n a_{i,\sigma(i)}.
Each term is a product of continuous coordinate functions; the sum is continuous.

Conclusion. det⁡\det is continuous, even polynomial in the entries.