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Exercise 1287Topology › Topology of Mn(ℝ)L1Added 4 Nov 2026

Completeness of $M_n(\mathbb{R})$

#completeness#Cauchy sequence#identification with R^{n^2}

Statement

Show that Mn(R)M_n(\mathbb{R}) equipped with the sup metric is complete.

Hint

Identify Mn(R)M_n(\mathbb{R}) with Rn2\mathbb{R}^{n^2}; use completeness of R\mathbb{R}.

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Solution

Identification. The map Φ:Mn(R)→Rn2\Phi:M_n(\mathbb{R})\to\mathbb{R}^{n^2} sending AA to its entries is an isometry for the sup metric.

Cauchy sequences. A Cauchy sequence in Mn(R)M_n(\mathbb{R}) corresponds to a Cauchy sequence in Rn2\mathbb{R}^{n^2}. Since Rn2\mathbb{R}^{n^2} is complete, it converges; identifying back gives convergence in Mn(R)M_n(\mathbb{R}).

Conclusion. Mn(R)M_n(\mathbb{R}) is complete.