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Exercise 1963Topology › Topology of Mn(ℝ)L1Added 4 Nov 2026

Classical closed subgroups of $GL_n(\mathbb{R})$

#closed subgroups#GL_n#SL_n#O_n#determinant

Statement

Show that the following subsets of Mn(R)M_n(\mathbb{R}) are closed:
SLn(R)={A:det⁡A=1},On(R)={A:ATA=In},Sn(R)={A:AT=A}.SL_n(\mathbb{R})=\{A:\det A=1\},\qquad O_n(\mathbb{R})=\{A:A^TA=I_n\},\qquad S_n(\mathbb{R})=\{A:A^T=A\}.

Hint

Each is the preimage of a closed set under a continuous map.

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Solution

SLnSL_n. The determinant det⁡:Mn(R)→R\det:M_n(\mathbb{R})\to\mathbb{R} is continuous (polynomial in the entries). SLn=det⁡−1({1})SL_n=\det^{-1}(\{1\}) is closed as preimage of the closed set {1}\{1\}.

OnO_n. The map Φ(A)=ATA−In\Phi(A)=A^TA-I_n is continuous into the symmetric matrices. On=Φ−1({0})O_n=\Phi^{-1}(\{0\}) is closed.

SnS_n. The map A↦AT−AA\mapsto A^T-A is linear (continuous). SnS_n is its kernel, hence closed.

Conclusion. SLnSL_n, OnO_n, SnS_n are closed subgroups (or subspace) of Mn(R)M_n(\mathbb{R}).