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Exercise 1154Logic, sets and proofs › Quantifiers and negationL1Added 3 Nov 2026

Existence and uniqueness proof

#existence#uniqueness#proof

Statement

Prove ∃!x∈R, 2x+1=5\exists! x\in\mathbb{R},\ 2x+1=5.

Hint

Solve the equation, then show uniqueness.

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Solution

Existence. x=2x=2 satisfies 2⋅2+1=52\cdot2+1=5.

Uniqueness. If 2x+1=52x+1=5, then 2x=42x=4, so x=2x=2. Unique.

Conclusion. x=2x=2 is the unique solution.