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Exercise 535Combinatorics › Pigeonhole principleL1Added 3 Nov 2026

Pairs summing to $2n+1$

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Statement

Show that among any n+1n+1 integers from {1,…,2n}\{1,\ldots,2n\}, some two sum to 2n+12n+1.

Hint

Pair the numbers as (1,2n),(2,2n−1),…,(n,n+1)(1,2n),(2,2n-1),\ldots,(n,n+1).

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Solution

Pairs. These nn pairs each sum to 2n+12n+1.

Pigeonhole. With n+1n+1 integers and nn pairs, some pair contains 22 chosen integers.

Conclusion. Those two sum to 2n+12n+1.