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Exercise 1813Combinatorics › Pigeonhole principleOlympiadAdded 3 Nov 2026

Subsets of fixed size

#pigeonhole#subsets#size

Statement

Show that among any (2nn)+1\binom{2n}{n}+1 subsets of a 2n2n-element set, two have the same size.

Hint

Wait: that's too many. Better problem: among any n+1n+1 subsets of an nn-element set, two have the same size.

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Solution

Sizes. Subsets of an nn-element set have sizes 0,1,…,n0,1,\ldots,n: n+1n+1 possible sizes.

Pigeonhole (corrected). With n+2n+2 subsets, two have the same size. With exactly n+1n+1 subsets, all sizes can be distinct.

Conclusion. n+2n+2 subsets guarantee two of the same size.