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Exercise 44Calculus › Single-variable calculus › Differentiation › Mean Value TheoremHigh schoolAdded 4 Nov 2026

Summary of the mean value theorem

#summary#MVT#Rolle

Statement

Summarize the mean value theorem and its consequences.

Hint

Review the statements and main applications.

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Solution

Rolle's theorem. If ff is continuous on [a,b][a,b], differentiable on ]a,b[]a,b[, and f(a)=f(b)f(a)=f(b), then f′f' vanishes somewhere in ]a,b[]a,b[.

Mean value theorem (Lagrange). If ff is continuous on [a,b][a,b] and differentiable on ]a,b[]a,b[, then there exists c∈]a,b[c\in]a,b[ with f(b)−f(a)=f′(c)(b−a)f(b)-f(a)=f'(c)(b-a).

Cauchy's extended MVT. Ratio form f(b)−f(a)g(b)−g(a)=f′(c)g′(c)\frac{f(b)-f(a)}{g(b)-g(a)}=\frac{f'(c)}{g'(c)} when g′≠0g'\ne0.

Consequences.
- f′=0⇒ff'=0\Rightarrow f constant.
- f′≥0⇒ff'\ge0\Rightarrow f nondecreasing; f′>0⇒f'>0\Rightarrow strictly increasing.
- Bounded derivative ⇒\Rightarrow Lipschitz.
- Convexity   ⟺  f′\iff f' nondecreasing.

Inequalities. sin⁡x<x\sin x<x, ln⁡x<x−1\ln x<x-1, ex>1+xe^x>1+x, arctan⁡t>t/(1+t2)\arctan t>t/(1+t^2).

Uniqueness of roots. Rolle + f′>0f'>0 gives at most one root.

Darboux theorem. f′f' has the intermediate value property.

Conclusion. The MVT is one of the most powerful tools in single-variable calculus, connecting derivatives to function behavior.