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Exercise 18Calculus › Single-variable calculus › Differentiation › Mean Value TheoremHigh schoolAdded 4 Nov 2026

Rolle's theorem on a polynomial

#Rolle#polynomial#existence

Statement

Let P(x)=x3−3x+1P(x)=x^3-3x+1. Show that P′P' has at least one root in ]−1,2[]-1,2[.

Hint

Check P(−1)=P(2)P(-1)=P(2) and apply Rolle's theorem.

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Solution

Values. P(−1)=−1+3+1=3P(-1)=-1+3+1=3 and P(2)=8−6+1=−1P(2)=8-6+1=-1.

Apply Rolle on [−1,2][-1,2]. PP is a polynomial, continuous on [−1,2][-1,2], differentiable on ]−1,2[]-1,2[, and P(−1)=P(2)=3P(-1)=P(2)=3. By Rolle, there exists c∈]−1,2[c\in]-1,2[ with P′(c)=0P'(c)=0.

Conclusion. P′P' vanishes on ]−1,2[]-1,2[.