Maths WorkshopMaths problems with full solutions
Exercise 1784Calculus › Multivariable calculus › Multiple integralsL1Added 3 Nov 2026

Linear change of variables

#change of variables#Jacobian#triangle

Statement

Compute I=∬D(x−y) dx dyI=\iint_D(x-y)\,dx\,dy where DD is bounded by x=0x=0, y=x+2y=x+2, y=−xy=-x, using the change of variables u=x+yu=x+y, v=x−yv=x-y.

Hint

Jacobian ∣J∣=1/2|J|=1/2; transform the bounds.

Show solutionHide solution

Solution

Transformed region. DD: 0≤u≤20\le u\le 2, −2≤v≤−u-2\le v\le -u.

Jacobian. x=u+v2x=\frac{u+v}{2}, y=u−v2y=\frac{u-v}{2}, so ∣J∣=12|J|=\frac12.

Compute.
I=12∫02∫−2−uv dv du=12∫02(u22−2)du=12(43−4)=−43.I=\frac12\int_0^2\int_{-2}^{-u}v\,dv\,du=\frac12\int_0^2\left(\frac{u^2}{2}-2\right)du=\frac12\left(\frac43-4\right)=-\frac43.

Conclusion. I=−4/3I=-4/3.