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Exercise 464Algebra › Equations and radicalsHigh schoolAdded 3 Nov 2026

A quadratic with complex roots

#quadratic#complex roots#discriminant

Statement

Solve in C\mathbb{C} the equation
x2+2x+5=0.x^2+2x+5=0.

Hint

The discriminant is negative. Use the complex square root.

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Solution

Discriminant. Δ=4−20=−16=(4i)2\Delta=4-20=-16=(4i)^2.

Roots.
x1=−2+4i2=−1+2i,x2=−2−4i2=−1−2i.x_1=\frac{-2+4i}{2}=-1+2i, \qquad x_2=\frac{-2-4i}{2}=-1-2i.

Conclusion. x∈{−1+2i, −1−2i}x\in\{-1+2i,\,-1-2i\}. Note that the roots are conjugate, as expected for a real polynomial.