Maths WorkshopMaths problems with full solutions
Exercise 1674Algebra › Equations and radicalsL1Added 3 Nov 2026

Counting real roots

#polynomial#real roots#derivative

Statement

Show that the equation x3−3x+1=0x^3-3x+1=0 has three distinct real roots.

Hint

Study the function f(x)=x3−3x+1f(x)=x^3-3x+1 and its derivative.

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Solution

Derivative. f′(x)=3x2−3=3(x−1)(x+1)f'(x)=3x^2-3=3(x-1)(x+1).

Critical points. f′f' vanishes at x=−1x=-1 and x=1x=1. f′<0f'<0 on ]−1,1[]-1,1[ (so ff decreases), f′>0f'>0 outside.

Values. f(−1)=−1+3+1=3>0f(-1)=-1+3+1=3>0; f(1)=1−3+1=−1<0f(1)=1-3+1=-1<0.

Limits. lim⁡−∞f=−∞\lim_{-\infty}f=-\infty, lim⁡+∞f=+∞\lim_{+\infty}f=+\infty.

Conclusion. By the intermediate value theorem, ff has one root in ]−∞,−1[]-\infty,-1[, one in ]−1,1[]-1,1[, one in ]1,+∞[]1,+\infty[. Three distinct real roots.