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Exercise 367Number theory › Divisibility and gcdHigh schoolAdded 2 Nov 2026

Computing LCM from divisibility

#lcm#divisibility#product

Statement

Given \divisibility(8303,2717)=19\divisibility(8303,2717)=19, compute lcm⁡(8303,2717)\operatorname{lcm}(8303,2717).

Hint

Use \divisibility(a,b)⋅lcm⁡(a,b)=ab\divisibility(a,b)\cdot\operatorname{lcm}(a,b)=ab.

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Solution

lcm⁡(8303,2717)=8303⋅271719=2255625119=1187329.\operatorname{lcm}(8303,2717)=\frac{8303\cdot2717}{19}=\frac{22556251}{19}=1187329.

Remark. This matches the Université Lyon 1 correction.