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Exercise 206Number theory › Divisibility and gcdHigh schoolAdded 2 Nov 2026

Finding divisors systematically

#divisors#enumeration#bounds

Statement

Find all positive divisors of 2020.

Hint

If d∣20d\mid20 and d>0d>0, then d≤20d\le20. Test d=1,…,20d=1,\ldots,20, or use 20=22⋅520=2^2\cdot5.

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Solution

Factorization. 20=22⋅520=2^2\cdot5. The divisors are 2a5b2^a5^b with 0≤a≤20\le a\le2, 0≤b≤10\le b\le1:
1,2,4,5,10,20.1,2,4,5,10,20.

Verification. 20=1⋅20=2⋅10=4⋅520=1\cdot20=2\cdot10=4\cdot5.