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Exercise 744Number theory › Divisibility and gcdL1Added 2 Nov 2026

If $a,b$ are coprime, so are $a+b$ and $ab$

#coprime#sum#product

Statement

Let a,ba,b be coprime positive integers. Show that \divisibility(a+b,ab)=1\divisibility(a+b,ab)=1.

Hint

Let pp be a prime dividing both a+ba+b and abab. Use Euclid's lemma.

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Solution

Prime argument. Suppose a prime pp divides a+ba+b and abab. Since p∣abp\mid ab and pp is prime, p∣ap\mid a or p∣bp\mid b.

If p∣ap\mid a, then from p∣a+bp\mid a+b we get p∣bp\mid b, contradicting \divisibility(a,b)=1\divisibility(a,b)=1. Similarly if p∣bp\mid b.

Conclusion. No prime divides both a+ba+b and abab, so \divisibility(a+b,ab)=1\divisibility(a+b,ab)=1.