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Exercise 905Linear algebra › DeterminantsL1Added 3 Nov 2026

Determinant of an orthogonal matrix

#orthogonal matrix#determinant#isometry

Statement

Let QQ be an orthogonal matrix, i.e. QTQ=IQ^T Q=I. Show that det⁡Q=±1\det Q=\pm1.

Hint

Take determinants of QTQ=IQ^T Q=I.

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Solution

Computation. From QTQ=IQ^T Q=I:
det⁡(QTQ)=det⁡I=1.\det(Q^T Q) = \det I = 1.
By multiplicativity of the determinant and det⁡(QT)=det⁡Q\det(Q^T)=\det Q:
det⁡(Q)det⁡(Q)=1.\det(Q)\det(Q) = 1.
So (det⁡Q)2=1(\det Q)^2=1, hence det⁡Q=±1\det Q = \pm1.

Interpretation. An orthogonal matrix represents an isometry of Rn\mathbb{R}^n. If det⁡Q=1\det Q=1, it is a rotation; if det⁡Q=−1\det Q=-1, it is a reflection composed with a rotation.