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Exercise 451Linear algebra › DeterminantsHigh schoolAdded 3 Nov 2026

Effect of row operations on the determinant

#row operations#determinant properties#multilinearity

Statement

Describe the effect of each elementary row operation on the determinant:

  1. Li↔LjL_i \leftrightarrow L_j (swap two rows);
  2. Li←λLiL_i \leftarrow \lambda L_i with λ≠0\lambda\neq 0 (multiply a row by λ\lambda);
  3. Li←Li+λLjL_i \leftarrow L_i + \lambda L_j with j≠ij\neq i (add a multiple of another row).
Hint

Use multilinearity and the alternating property of the determinant.

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Solution

1. Swapping. The determinant changes sign: det⁡=−det⁡original\det = -\det_{\text{original}}. This follows from the alternating property (the determinant is zero when two rows are equal, and swapping is an odd permutation).

2. Scaling. Multiplying a row by λ\lambda multiplies the determinant by λ\lambda: det⁡=λ⋅det⁡original\det = \lambda\cdot\det_{\text{original}}. This follows from linearity in each row.

3. Adding a multiple. Adding a multiple of one row to another leaves the determinant unchanged. Indeed, writing the new row as Li+λLjL_i+\lambda L_j, linearity gives det⁡(Li+λLj,…)=det⁡(Li,…)+λdet⁡(Lj,…)\det(L_i+\lambda L_j,\ldots)=\det(L_i,\ldots)+\lambda\det(L_j,\ldots), and the second determinant has two equal rows, so it is zero.

Conclusion. Swapping changes sign; scaling by λ\lambda scales by λ\lambda; adding a multiple leaves the determinant unchanged. These rules are used to simplify determinant computations.