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Exercise 429Algebra › Complex numbersHigh schoolAdded 3 Nov 2026

Modulus and argument

#modulus#argument#trigonometric form

Statement

Find the modulus and argument of z=1+i3z=1+i\sqrt3, then write zz in trigonometric form.

Hint

∣z∣=a2+b2|z|=\sqrt{a^2+b^2}, arg⁡(z)\arg(z) determined by cos⁡θ=a/∣z∣\cos\theta=a/|z|, sin⁡θ=b/∣z∣\sin\theta=b/|z|.

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Solution

Modulus. ∣z∣=1+3=2|z|=\sqrt{1+3}=2.

Argument. cos⁡θ=1/2\cos\theta=1/2, sin⁡θ=3/2\sin\theta=\sqrt3/2, so θ=π/3\theta=\pi/3.

Trigonometric form. z=2(cos⁡π3+isin⁡π3)=2eiπ/3z=2(\cos\frac\pi3+i\sin\frac\pi3)=2e^{i\pi/3}.

Conclusion. ∣z∣=2|z|=2, arg⁡(z)=π/3\arg(z)=\pi/3 (mod 2π2\pi), z=2eiπ/3z=2e^{i\pi/3}.