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Exercise 220Algebra › Complex numbersHigh schoolAdded 3 Nov 2026

Basic operations on complex numbers

#complex numbers#addition#multiplication#conjugate

Statement

Let z1=2+3iz_1=2+3i and z2=1−2iz_2=1-2i. Compute z1+z2z_1+z_2, z1−z2z_1-z_2, z1z2z_1z_2, z1ˉ\bar{z_1}, and z1/z2z_1/z_2.

Hint

Use i2=−1i^2=-1. For the quotient, multiply numerator and denominator by z2ˉ\bar{z_2}.

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Solution

Sum. z1+z2=3+iz_1+z_2=3+i.

Difference. z1−z2=1+5iz_1-z_2=1+5i.

Product. z1z2=(2+3i)(1−2i)=2−4i+3i−6i2=2−i+6=8−iz_1z_2=(2+3i)(1-2i)=2-4i+3i-6i^2=2-i+6=8-i.

Conjugate. z1ˉ=2−3i\bar{z_1}=2-3i.

Quotient.
z1z2=(2+3i)(1+2i)(1−2i)(1+2i)=2+4i+3i+6i21+4=−4+7i5=−45+75i.\frac{z_1}{z_2}=\frac{(2+3i)(1+2i)}{(1-2i)(1+2i)}=\frac{2+4i+3i+6i^2}{1+4}=\frac{-4+7i}{5}=-\frac45+\frac75 i.

Conclusion. z1+z2=3+iz_1+z_2=3+i, z1−z2=1+5iz_1-z_2=1+5i, z1z2=8−iz_1z_2=8-i, z1ˉ=2−3i\bar{z_1}=2-3i, z1/z2=−4/5+7i/5z_1/z_2=-4/5+7i/5.