Maths WorkshopMaths problems with full solutions
Exercise 421Algebra › Complex numbersHigh schoolAdded 3 Nov 2026

Midpoint and centroid in the complex plane

#midpoint#centroid#complex plane

Statement

Let AA, BB, CC have affixes zA,zB,zCz_A,z_B,z_C. Show that:
- the midpoint of ABAB has affix zA+zB2\frac{z_A+z_B}{2};
- the centroid of ABCABC has affix zA+zB+zC3\frac{z_A+z_B+z_C}{3}.

Hint

Express the coordinates.

Show solutionHide solution

Solution

Midpoint. If zA=a+biz_A=a+bi and zB=c+diz_B=c+di, the midpoint has coordinates ((a+c)/2,(b+d)/2)((a+c)/2,(b+d)/2), affix a+c2+ib+d2=zA+zB2\frac{a+c}{2}+i\frac{b+d}{2}=\frac{z_A+z_B}{2}.

Centroid. Similarly, the centroid has coordinates the average of the three coordinates, giving affix zA+zB+zC3\frac{z_A+z_B+z_C}{3}.

Conclusion. Both formulas hold; they are the natural complex analogues of vector averaging.