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Exercise 1568Algebra › Complex numbersOlympiadAdded 3 Nov 2026

An ellipse via a modulus equation

#ellipse#locus#modulus

Statement

Describe the set of points MM with affix zz such that ∣z−1∣+∣z+1∣=4|z-1|+|z+1|=4.

Hint

Sum of distances from MM to two fixed points equals a constant.

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Solution

Interpretation. ∣z−1∣|z-1| is the distance from MM to A(1,0)A(1,0) and ∣z+1∣|z+1| is the distance from MM to B(−1,0)B(-1,0). The equation states that MA+MB=4MA+MB=4.

Ellipse. The set of points whose sum of distances to two fixed points is constant is an ellipse with foci AA and BB. The constant is 2a=42a=4, so a=2a=2; the focal distance is 2c=22c=2, so c=1c=1. Then b2=a2−c2=3b^2=a^2-c^2=3.

Conclusion. The locus is the ellipse with foci (±1,0)(\pm1,0), semi-major axis 22, semi-minor axis 3\sqrt3: x24+y23=1\frac{x^2}{4}+\frac{y^2}{3}=1.