Exercise 828Algebra › Complex numbersHigh schoolAdded 3 Nov 2026 Linearizing powers of cosine #De Moivre#linearization#cos StatementExpress cos3θ\cos^3\thetacos3θ as a linear combination of cosθ\cos\thetacosθ and cos3θ\cos 3\thetacos3θ. HintUse cosθ=(eiθ+e−iθ)/2\cos\theta=(e^{i\theta}+e^{-i\theta})/2cosθ=(eiθ+e−iθ)/2 and expand. Show solutionHide solutionSolutionExpansion.cos3θ=(eiθ+e−iθ2)3=18(e3iθ+3eiθ+3e−iθ+e−3iθ).\cos^3\theta=\left(\frac{e^{i\theta}+e^{-i\theta}}{2}\right)^3=\frac18(e^{3i\theta}+3e^{i\theta}+3e^{-i\theta}+e^{-3i\theta}).cos3θ=(2eiθ+e−iθ)3=81(e3iθ+3eiθ+3e−iθ+e−3iθ).Regroup.=18[(e3iθ+e−3iθ)+3(eiθ+e−iθ)]=18[2cos3θ+6cosθ]=cos3θ+3cosθ4.=\frac18[(e^{3i\theta}+e^{-3i\theta})+3(e^{i\theta}+e^{-i\theta})]=\frac18[2\cos3\theta+6\cos\theta]=\frac{\cos3\theta+3\cos\theta}{4}.=81[(e3iθ+e−3iθ)+3(eiθ+e−iθ)]=81[2cos3θ+6cosθ]=4cos3θ+3cosθ.Conclusion. cos3θ=3cosθ+cos3θ4\cos^3\theta=\frac{3\cos\theta+\cos3\theta}{4}cos3θ=43cosθ+cos3θ.