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Exercise 424Algebra › Complex numbersHigh schoolAdded 3 Nov 2026

The cube roots of unity

#cube roots#unity#cyclic

Statement

Find the cube roots of unity in algebraic form.

Hint

Solve z3=1z^3=1, or note z3−1=(z−1)(z2+z+1)z^3-1=(z-1)(z^2+z+1).

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Solution

Factor. z3−1=(z−1)(z2+z+1)z^3-1=(z-1)(z^2+z+1).

Roots. z=1z=1 or z2+z+1=0z^2+z+1=0.

Quadratic roots. z=(−1±i3)/2z=(-1\pm i\sqrt3)/2.

Notation. Let j=e2iπ/3=(−1+i3)/2j=e^{2i\pi/3}=(-1+i\sqrt3)/2. Then jˉ=j2=(−1−i3)/2\bar j=j^2=(-1-i\sqrt3)/2.

Conclusion. The cube roots of unity are 1,j,j21, j, j^2, with 1+j+j2=01+j+j^2=0.