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Exercise 415Combinatorics › Binomial coefficientsHigh schoolAdded 3 Nov 2026

Sum with $3^k$

#binomial#power sum#3^k

Statement

Compute ∑k=0n3k(nk)\sum_{k=0}^{n}3^k\binom{n}{k}.

Hint

Binomial theorem with a=1a=1, b=3b=3.

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Solution

Binomial theorem. (1+3)n=4n=∑k(nk)3k(1+3)^n=4^n=\sum_k\binom{n}{k}3^k.

Conclusion. ∑k3k(nk)=4n\sum_k 3^k\binom{n}{k}=4^n.