Definition and basic values

Compute.
$$\binom{5}{2}=\frac{5!}{2!\,3!}=\frac{120}{2\cdot 6}=10,$$
$$\binom{7}{0}=1,\qquad \binom{7}{7}=1,$$
$$\binom{10}{3}=\frac{10!}{3!\,7!}=\frac{10\cdot 9\cdot 8}{6}=120.$$

Conclusion. $\binom{5}{2}=10$, $\binom{7}{0}=1$, $\binom{7}{7}=1$, $\binom{10}{3}=120$.