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Exercise 409Combinatorics › Binomial coefficientsHigh schoolAdded 3 Nov 2026

Recurrence for coefficients

#recurrence#Pascal#coefficients

Statement

Let an=(n2)a_n=\binom{n}{2}. Find a recurrence for ana_n and solve it.

Hint

(n2)=(n−12)+(n−1)\binom{n}{2}=\binom{n-1}{2}+(n-1), or use an−an−1=n−1a_n-a_{n-1}=n-1.

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Solution

Recurrence. an−an−1=(n2)−(n−12)=n−1a_n-a_{n-1}=\binom{n}{2}-\binom{n-1}{2}=n-1 (from Pascal: (n2)=(n−11)+(n−12)\binom{n}{2}=\binom{n-1}{1}+\binom{n-1}{2}).

Solve. an=∑k=1n(k−1)+a1=n(n−1)2a_n=\sum_{k=1}^{n}(k-1)+a_1=\frac{n(n-1)}{2}.

Conclusion. an=n(n−1)2a_n=\frac{n(n-1)}{2}.