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Exercise 809Combinatorics › Binomial coefficientsOlympiadAdded 3 Nov 2026

Multinomial identity

#multinomial#identity#coefficient

Statement

Show that ∑i+j+k=nn!i!j!k!=3n\sum_{i+j+k=n}\frac{n!}{i!j!k!}=3^n.

Hint

This is the multinomial theorem with (1+1+1)n(1+1+1)^n.

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Solution

Multinomial. (1+1+1)n=∑i+j+k=nn!i!j!k!1i1j1k(1+1+1)^n=\sum_{i+j+k=n}\frac{n!}{i!j!k!}1^i1^j1^k.

Conclusion. ∑i+j+k=nn!i!j!k!=3n\sum_{i+j+k=n}\frac{n!}{i!j!k!}=3^n.