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Exercise 2089Combinatorics › Binomial coefficientsOlympiadAdded 3 Nov 2026

A challenging binomial sum

#binomial#sum#generating function

Statement

Compute ∑k=0n(nk)1k+1\sum_{k=0}^{n}\binom{n}{k}\frac{1}{k+1}.

Hint

1k+1(nk)=1n+1(n+1k+1)\frac{1}{k+1}\binom{n}{k}=\frac{1}{n+1}\binom{n+1}{k+1}.

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Solution

Rewrite. 1k+1(nk)=1n+1(n+1k+1)\frac{1}{k+1}\binom{n}{k}=\frac{1}{n+1}\binom{n+1}{k+1}.

Sum. ∑k=0n1k+1(nk)=1n+1∑k=0n(n+1k+1)=1n+1(2n+1−1)\sum_{k=0}^{n}\frac{1}{k+1}\binom{n}{k}=\frac{1}{n+1}\sum_{k=0}^{n}\binom{n+1}{k+1}=\frac{1}{n+1}(2^{n+1}-1).

Conclusion. ∑k=0n(nk)k+1=2n+1−1n+1\sum_{k=0}^{n}\frac{\binom{n}{k}}{k+1}=\frac{2^{n+1}-1}{n+1}.