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Exercise 1535Combinatorics › Binomial coefficientsOlympiadAdded 3 Nov 2026

Approximation via binomial theorem

#approximation#binomial#sqrt

Statement

Use the binomial theorem to approximate 1.02\sqrt{1.02} to 4 decimal places.

Hint

(1+x)1/2=1+x2−x28+⋯(1+x)^{1/2}=1+\frac{x}{2}-\frac{x^2}{8}+\cdots.

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Solution

Binomial series. (1+x)1/2=1+x2−x28+x316−⋯(1+x)^{1/2}=1+\frac{x}{2}-\frac{x^2}{8}+\frac{x^3}{16}-\cdots.

At x=0.02x=0.02. 1.02≈1+0.01−0.00048+0.00000816≈1.01−0.00005+0.0000005=1.0099505\sqrt{1.02}\approx 1+0.01-\frac{0.0004}{8}+\frac{0.000008}{16}\approx1.01-0.00005+0.0000005=1.0099505.

Conclusion. 1.02≈1.00995\sqrt{1.02}\approx 1.00995.