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Exercise 356Calculus › Single-variable calculus › SequencesL1Added 2 Nov 2026

A telescoping product

#telescoping#products#factoring

Statement

Let Pn=∏k=2n(1−1k2)P_n=\displaystyle\prod_{k=2}^n\left(1-\frac1{k^2}\right). Compute PnP_n and its limit.

Hint

Factor 1−1k2=(k−1)(k+1)k21-\frac1{k^2}=\frac{(k-1)(k+1)}{k^2} and write out the product.

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Solution

Factoring.
Pn=∏k=2nk−1k⋅∏k=2nk+1k.P_n=\prod_{k=2}^n\frac{k-1}k\cdot\prod_{k=2}^n\frac{k+1}k.

First product. 12⋅23⋯n−1n=1n\frac12\cdot\frac23\cdots\frac{n-1}n=\frac1n.

Second product. 32⋅43⋯n+1n=n+12\frac32\cdot\frac43\cdots\frac{n+1}n=\frac{n+1}2.

Result.
Pn=n+12n⟶12.P_n=\frac{n+1}{2n}\longrightarrow\frac12.