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Exercise 1928Linear algebra › Vector spaces and subspacesL1Added 3 Nov 2026

Sum of two planes in $\mathbb{R}^3$

#sum#intersection#planes

Statement

Let F={x+y+z=0}F=\{x+y+z=0\} and G={x−y=0}G=\{x-y=0\} in R3\mathbb{R}^3. Compute F∩GF\cap G, F+GF+G, and determine whether FF and GG are supplementary.

Hint

Compute the intersection first, then apply dim⁡(F+G)=dim⁡F+dim⁡G−dim⁡(F∩G)\dim(F+G)=\dim F+\dim G-\dim(F\cap G).

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Solution

Intersection. Solve x+y+z=0x+y+z=0 and x=yx=y: 2x+z=02x+z=0, so z=−2xz=-2x. Thus F∩G=span⁡((1,1,−2))F\cap G=\operatorname{span}((1,1,-2)), dimension 11.

Sum. dim⁡(F+G)=2+2−1=3\dim(F+G)=2+2-1=3, so F+G=R3F+G=\mathbb{R}^3.

Supplementary? For FF and GG to be supplementary, we need F∩G={0}F\cap G=\{0\}, but here the intersection has dimension 11. So they are not supplementary.

Conclusion. F∩GF\cap G is a line, F+G=R3F+G=\mathbb{R}^3, but F⊕G≠R3F\oplus G\neq\mathbb{R}^3 (they are not in direct sum).