Exercise 1192Topology › Topology of ℝⁿL1Added 3 Nov 2026
Continuity versus iterated limits
#iterated limits#continuity#subtleties
Statement
Show that (with ) has iterated limits along both axes but no limit at the origin.
Hint
Compute limits along and , then along .
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Solution
Iterated limits. , : so .
Diagonal. Along : , so the limit along this path is .
Conclusion. Iterated limits exist and coincide, but the two-dimensional limit does not: is not continuous at the origin.