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Exercise 1889Topology › Topology of ℝL1Added 3 Nov 2026

Limit superior and limit inferior

#limit superior#limit inferior#sequences

Statement

Compute lim sup⁡\limsup and lim inf⁡\liminf of un=(−1)n(1+1n)u_n=(-1)^n\left(1+\frac1n\right).

Hint

Consider even and odd subsequences.

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Solution

Even. u2k=1+12k→1u_{2k}=1+\frac{1}{2k}\to1.

Odd. u2k+1=−(1+12k+1)→−1u_{2k+1}=-(1+\frac{1}{2k+1})\to-1.

Conclusion. lim sup⁡un=1\limsup u_n=1, lim inf⁡un=−1\liminf u_n=-1; the sequence has no limit.