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Exercise 1184Topology › Topology of ℝL1Added 3 Nov 2026

Interior, closure, boundary

#interior#closure#boundary

Statement

For A=]0,1]∪{2}A=]0,1]\cup\{2\}, compute the interior, closure, and boundary of AA.

Hint

A˚\mathring A = union of open subsets of AA; A‾\overline A = smallest closed set containing AA; ∂A=A‾∖A˚\partial A=\overline A\setminus\mathring A.

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Solution

Interior. A˚=]0,1[\mathring A=]0,1[: 11 is not interior (every ball around 11 hits the complement), 22 is not interior (isolated).

Closure. A‾=[0,1]∪{2}\overline A=[0,1]\cup\{2\}: the limit points of ]0,1]]0,1] are in [0,1][0,1]; 22 is already in AA.

Boundary. ∂A={0,1,2}\partial A=\{0,1,2\}.

Conclusion. Interior ]0,1[]0,1[, closure [0,1]∪{2}[0,1]\cup\{2\}, boundary {0,1,2}\{0,1,2\}.