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Exercise 791Calculus › Single-variable calculus › Series › Convergence testsL1Added 2 Nov 2026

The root test

#root test#Cauchy#exponential limits

Statement

Decide the nature of
∑(n2n+1)n,∑13n(1+1n)n2,∑(1−1n)n2.\sum\left(\frac n{2n+1}\right)^n,\qquad\sum\frac1{3^n}\left(1+\frac1n\right)^{n^2},\qquad\sum\left(1-\frac1n\right)^{n^2}.

Hint

If unn→L\sqrt[n]{u_n}\to L, the series converges for L<1L<1 and diverges for L>1L>1.

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Solution

1. unn=n2n+1→12<1\sqrt[n]{u_n}=\frac n{2n+1}\to\frac12<1: converges.

2. unn=13(1+1n)n→e3≈0.906<1\sqrt[n]{u_n}=\frac13\left(1+\frac1n\right)^n\to\frac e3\approx0.906<1: converges.

3. unn=(1−1n)n→1e<1\sqrt[n]{u_n}=\left(1-\frac1n\right)^n\to\frac1e<1: converges.

Why the root test? The exponent n2n^2 or nn makes the ratio test awkward but the nn-th root easy.

Remark. The root test is more powerful than the ratio test: whenever the ratio test gives an answer, so does the root test (the converse is false).