Exercise 279Logic, sets and proofs › Sets and mapsHigh schoolAdded 3 Nov 2026
Subset relations
#subset#inclusion#definition
Statement
Define and prove that for every set .
Hint
means every element of is an element of . For the empty set, prove by contradiction.
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Solution
Definition. .
Empty set. Suppose . Then there exists with . But has no elements, contradiction.
Conclusion. for every set (vacuous truth).