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Exercise 576Logic, sets and proofs › Sets and mapsHigh schoolAdded 3 Nov 2026

The power set

#power set#subsets#cardinality

Statement

Let A={1,2,3}A=\{1,2,3\}. List all elements of P(A)\mathcal{P}(A) and give its cardinality.

Hint

A set with nn elements has 2n2^n subsets.

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Solution

List.
P(A)={∅,{1},{2},{3},{1,2},{1,3},{2,3},{1,2,3}}.\mathcal{P}(A)=\{\emptyset,\{1\},\{2\},\{3\},\{1,2\},\{1,3\},\{2,3\},\{1,2,3\}\}.

Cardinality. ∣P(A)∣=23=8|\mathcal{P}(A)|=2^3=8.

Conclusion. P(A)\mathcal{P}(A) has 88 elements.