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Exercise 573Logic, sets and proofs › Sets and mapsHigh schoolAdded 3 Nov 2026

Cartesian product

#Cartesian product#ordered pair#cardinality

Statement

Let A={1,2}A=\{1,2\} and B={a,b,c}B=\{a,b,c\}. Compute A×BA\times B and B×AB\times A. Compare their cardinalities.

Hint

A×B={(x,y):x∈A, y∈B}A\times B=\{(x,y):x\in A,\ y\in B\}.

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Solution

A×BA\times B. {(1,a),(1,b),(1,c),(2,a),(2,b),(2,c)}\{(1,a),(1,b),(1,c),(2,a),(2,b),(2,c)\}.

B×AB\times A. {(a,1),(a,2),(b,1),(b,2),(c,1),(c,2)}\{(a,1),(a,2),(b,1),(b,2),(c,1),(c,2)\}.

Cardinalities. ∣A×B∣=2⋅3=6|A\times B|=2\cdot3=6, ∣B×A∣=3⋅2=6|B\times A|=3\cdot2=6. Equal, but the sets differ (different elements).

Conclusion. A×B≠B×AA\times B\neq B\times A in general, though ∣A×B∣=∣B×A∣|A\times B|=|B\times A|.