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Exercise 45Calculus › Single-variable calculus › Integration › Riemann integralHigh schoolAdded 5 Nov 2026

Additivity over adjacent intervals

#additivity#step function#split

Statement

Let f:[a,c]→Rf:[a,c]\to\mathbb{R} be a step function, and b∈]a,c[b\in]a,c[. Show that
∫acf=∫abf+∫bcf.\int_a^cf=\int_a^bf+\int_b^cf.

Hint

Add bb to the subdivision of ff and compare sums.

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Solution

Refinement. Let σ\sigma be a subdivision of [a,c][a,c] adapted to ff. Set σ′=σ∪{b}\sigma'=\sigma\cup\{b\}: still adapted to ff. The sum over σ′\sigma' splits into the sum over the parts of [a,b][a,b] and over the parts of [b,c][b,c].

Sum. ∑kΔkck=∑Δk⊆[a,b]ckΔk+∑Δk⊆[b,c]ckΔk=∫abf+∫bcf\sum_{k}\Delta_kc_k=\sum_{\Delta_k\subseteq[a,b]}c_k\Delta_k+\sum_{\Delta_k\subseteq[b,c]}c_k\Delta_k=\int_a^bf+\int_b^cf.

Conclusion. Chasles' relation holds for step functions.